Author Topic: NP → (D) N' ... DP → D NP  (Read 3412 times)

Offline Jase

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NP → (D) N' ... DP → D NP
« on: March 16, 2014, 10:25:52 PM »
In the beginning of the discussion about X-bar Theory, Carnie lists NP → (D) N' as the first PSR (chapter 6), but in the following chapter he adjusts the rules to incorporate the determiner phrase, so that we now have DP → D NP. Does this mean that I should delete the first rule from my thinking? I'm trying to keep an updated list of PSRs as I progress through this study, but I'm not sure if I should just delete that and from now on just have NP → N' without any determiner/specifier slot, since this has been moved outside of the NP.

NP → (D) N'



DP → D NP



Thanks for taking the time to look at these things. I wouldn't bother you with such simplistic stuff, but I don't have anyone else to turn to with questions. I really appreciate it.
Just getting into syntax. Appreciate any help I can find here.
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Offline Daniel

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Re: NP → (D) N' ... DP → D NP
« Reply #1 on: March 17, 2014, 09:36:24 AM »
Carnie frequently updates the grammar by eliminating earlier rules, even entire lines of argumentation. It's a process, and the grammar is constantly evolving.
The book is pretty good but that's my biggest objection, just because it's confusing.
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Offline Jase

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Re: NP → (D) N' ... DP → D NP
« Reply #2 on: March 17, 2014, 01:44:09 PM »
Carnie frequently updates the grammar by eliminating earlier rules, even entire lines of argumentation. It's a process, and the grammar is constantly evolving.
The book is pretty good but that's my biggest objection, just because it's confusing.

In other words, I can delete the older rule at this point? Is NP → (D) N no longer a necessary rule?
Just getting into syntax. Appreciate any help I can find here.
χάριν ἔχω ὑμῖν πᾶσιν τοῖς βοηθοῦσί μοι φίλοις.

Offline Daniel

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Re: NP → (D) N' ... DP → D NP
« Reply #3 on: March 17, 2014, 01:54:50 PM »
Correct.
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